Essay CMIS 102 Week 6 Hands On Lab

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## CMIS 102 Week 6 Hands On Lab

**Overview**

This hands-on lab allows you to follow and experiment with the critical steps of developing a program including the program description, analysis, test plan, design and implementation with C code. The example provided uses sequential, repetition statements and nested repetition statements.

**Program Description**

This program will calculate the average of 3 exams for 5 students. The program will ask the user to enter 5 student names. For each of the students, the program will ask for 3 exam scores. The average exam score for each student will be calculated and printed.

**Analysis**

I will use sequential and repetition programming statements.

I will define one String to store the student name: StudentName.

I will define three Float numbers: Examvalue, Sum, Avg to store exam values the sum of the exams and the average of the exams.

The sum will be calculated by this formula:

Sum = Sum + Examvalue

For example, if the first value entered was 80.0 and second was 90.0 and the third exam was 100.0: sum = sum + Examvalue = 0.0 + 80.0

sum = 80.0 + 90.0 = 170.0

sum = 170.0 + 100.0 = 270.0

Avg is then calculated as:

Avg = sum/3.0

For example 270.0/3.0 = 90.0

A nested repetition loop can be used to loop through each of the 5 students and each of the 3 exams:

For (students=0; students <5; students++) For (exams=0;exams<3;exams++) End For End For Sum values will need to be reset for each student to ensure only one student data is used for calculations each time. **Test Plan**

To verify this program is working properly the input values could be used for testing:

Test Case | Input | Expected Output |
---|---|---|

1 | Studentname=Chris Examvalue1=80.0 Examvalue2=90.0 Examvalue3=100.0 Studentname=John Examvalue1=70.0 Examvalue2=90.0 Examvalue3=80.0 Studentname=Sally Examvalue1=100.0 Examvalue2=100.0 Examvalue3=100.0 Studentname=Pat Examvalue1=50.0 Eexamvalue2=70.0 Examvalue3=60.0 Studentname=Sam Examvalue1=90.0 Examvalue2=95.0 Examvalue3=100.0 | Average for Chris is 90.0 Average for John is 80.0 Average for Sally is 100.0 Average for Pat is 60.0 Average for Sam is 95.0 |

**Pseudocode**

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | `// This program will calculate the average of 3 exams for 5 students` `// Declare variables` `Declare StudentName ` `as` `String` `Declare ExamValue, Sum, Avg ` `as` `Float` `// Loop through 5 Students` `For (students=0; students <5 ; students++)` ` ` `// reset Sum to 0` ` ` `Set Sum =0.0` ` ` `Print` `“Enter Student Name”` ` ` `Input StudentName` ` ` `// Nested Loop for Exams` ` ` `For (exams=0; exams < 3; exams++)` ` ` `Print` `“Enter exam grade: \n”` ` ` `Input ExamValue` ` ` `Set Sum = Sum + ExamValue` ` ` `End` `For` ` ` `Set Avg = Sum/3.0` ` ` `Print` `“Average ` `for` `“ + StudentName + “ is “ + Avg` ` ` `End` `For` |

**C Code**

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 | `The following is the C Code that will compile in execute in the online compilers.` `// C code` `// This program will calculate the average of 3 exams for 5 students. // Developer: Faculty CMIS102` `// Date: Jan 31, XXXX` `#` `include` `<stdio.h>` `int main ()` `{` ` ` `/* variable definition: */` ` ` `char StudentName[100];` ` ` `float ExamValue, Sum, Avg;` ` ` `int students,exams;` ` ` `// Loop through 5 Students` ` ` `for` `(students=0; students <5 ; students++) {` ` ` `// reset Sum to 0` ` ` `Sum =0.0;` ` ` `printf(` `"Enter Student Name \n"` `);` ` ` `scanf(` `"%s"` `, StudentName);` ` ` `// Nested Loop for Exams` ` ` `for` `(exams=0; exams < 3; exams++)` ` ` `{` ` ` `printf (` `"Enter exam grade: \n"` `);` ` ` `scanf(` `"%f"` `, &ExamValue);` ` ` `Sum += ExamValue;` ` ` `}` ` ` `Avg = Sum/3.0;` ` ` `printf( ` `"Average for %s is %f\n"` `,StudentName,Avg);` ` ` `}` ` ` `return` `0; ` `}` |

Setting up the code and the input parameters in ideone.com:

Note the Student and ExamValues for this run were:

John: 90.0 80.0 100.0

Jim: 80.0 70.0 90.0

Joe: 70.0 100.0 100.0

Sally: 100.0 95.0 91.0

Sam: 30.0 54.0 68.0

You can change these values to any valid integer values to match your test cases.

**Learning Exercises for you to complete**

- Modify the code to be able to input an undetermined number of students. You will still only have 3 exams for each student. Support your experimentation with screen captures of executing the new code.
- Prepare a new test table with at least 3 distinct test cases listing input and expected output for the code you created after step 1.
- What is the line of code doing?

char StudentName[100];

(Hint: We haven’t covered arrays, but a String can be thought of as an array of characters) ? - What would happen if you moved the Set Sum = 0.0 from inside the for loop to right after the declaration. For example:

// Declare variables

Declare StudentName as String Declare ExamValue, Sum, Avg as Float

// Initialize Sum Set Sum = 0.0;

Support your experimentation with screen captures of executing the new code.